Question

In a comman-base connection, a certain

transistor has an emitter current of

10mA and collector current of 9.8 mA.

Calculate the value of the base current.....

please answer it right...​

Answer 1

Answer:

let Ie be emitter current Ib be base current and Ic be collector current.

Ie=lb+Ic

10mA=Ib+ 9.8mA

Ib= 0.2mA.

Answer 2

Answer:

Base current in common base connection in transition is 0.2 mA.

Explanation:

In common base transistor  input is supplied through emitter and base terminal and output is taken through collector and base terminal.

In transistor we have a relation between  collector emitter and base current.

                  $I_{e}= I_{b} + I_{c}$  --------(i)

representing collector, base and emitter current

Given :            

   $I_{e} = 10 mA\\ I_{c} = 9.8 mA$

so putting in equation (i)    

   $I_{b}= I_{e} - I_{c}\\\\I_{b} = (10 - 9.8 )mA\\\\I_{b} = 0.2 mA$

Hence base current is 0.2 mA