Question

In a committee, 50 people speak French, 20 speak Spanish and 10 speak both Spanish and French. How many speak at least One Of these two languages?

Answer 1

Let us assume that ‘S’ be the set of people who speak Spanish.
‘F’ be the set of people who speak French.

number of people who speak Spanish , n(S) = 20
number of people who speak French , n(F) = 50
number of people who speak both Spanish and French , $n(S\cap F)$ = 10

we have to find number of people who speak at least one of these two languages , n(S U F)

use formula,
$n(S\cup F) = n(S) + n(F) - n(S\cap F)$

= 20 + 50 - 10

= 60

Thus, 60 people speak at least one of these languages.

Answer 2

Answer:

60

Step-by-step explanation:

Let the number of people who speak French = n(F) = 50,

number of people who speak Spanish = n(S) = 20 ,

number of people who speak both

French and Spanish = n(F∩S) = 10 ,

Number of people who speak at least

One of these two languages = n(F∪S) = ?

We know that ,

n(F∪S) = n(F) + n(S) - n(F∩S)

= 50 + 20 -10

= 70 - 10

= 60

∴ n(F∪S) = 60

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