Question

In a common emitter amplifier the output resistance is 4000 ohm and the input resistance is 1kilo ohm. If the peak value of the signal voltage is 10m V and beeta value 50 , then the peak value of the output voltage is ​

Answer 1

Answer:

Peak value of output voltage is 2 V

Explanation:

As we know that the transistor is given here as common emitter

so we will have

$\frac{V_{out}}{V_{in}} = \frac{i_c R_{out}}{i_b R_{in}}$

now we know that for common emitter we will have

$\frac{i_c}{i_b} = \beta$

$\frac{i_c}{i_b} = 50$

also we know

$R_{out} = 4000 ohm$

$R_{in} = 1000 ohm$

now we have

$V_{out} = (10mV)\frac{50 \times 4000}{1000}$

$V_{out} = 2 V$

#Learn

Topic : Transistor

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