Question

In a common emitter transistor circuit , the base current is 40 microampere yhen vbe is

Answer 1

Solution:-

V$_{B}$+IR+E= V$_{E}$

V$_{B}$-V$_{E}$= IR-E

=> 9800×10∧3×10∧-6-E

=>9.8-10

=> 0.2V

In a common emitter transistor circuit , the base current is 40 microampere yhen vbe is 0.2V

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@GauravSaxena01