Question

In a common emitter transistor circuit the base current is 40

Answer 1

The value of $V_{BE}$ is 0.2 V.

Explanation:

=> It is given that,

Base current, $I_{B}$ = 40μA = 40 * 10⁻⁶ A

Resistance in the base region, $R_{B}$ = 245kΩ

=> By applying Kirchhoffs Voltage Law, we have

Now, Vinput $= V_{BE} + I_{B}R_{B}$

$V_{BE}$ = Vinput - $I_{B}R_{B}$

      = 10 - 40 * 10⁻⁶ * 245 * 10³

      = 10 - 9800 * 10⁻³

      = 10 - 9.8

      = 0.2 V

Thus, the value of $V_{BE}$ is 0.2 V.

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