In a community there are equal number of males and famles. Suppose 5% of the males and 2% of the females are disabled.A person is chosen randomly. If the person is male, what is the probability that he is disabled?
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1/40 is the probability
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Answer:
1/40
Step-by-step explanation:
let male population be 'x'
so female population is also 'x'
Total population = x + x
= 2x
Now disabled male population = 5% of x
= 5% of x
= x/20
So, P(disabled male ) = x/20 ÷ 2x
= x/20 × 1/2x
= 1/40
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