Question

in a community, two neighbours have rectangular back yard having the same are of 650sq . Meter if the breadth of first backyard is 25meter and the breadth of second backyard is 5 meter, find which backyard will more fencing and by how much?​

Answer 1

Answer:

Second one and by 168 m

Step-by-step explanation:

Formula for length of first backyard will be Area/Breadth

650/25 = 26 m

Apply the same formula for the second one too.

A/B

650/5 = 130 m

Perimeter formula for fence

2( l+b)

2(25+26)

102 m

Same formula

2(130 + 5)

270 m

Difference = 270 - 102 m

168 m

Answer 2

Answer:

Step-by-step explanation:LET THE LENGTH OF FIRST BACCKYARD BE X

BREADTH=25M

AREA=650

AREA OF RECTANGLE=L*B

ACCORDING TO THE QUESTION

L*B=650

L*25=650

L=650/25

=26M

PERIMETER TO FIND FENCE=2(L+B)

                                              =2(26+25)

                                               =2*51

                                              =102m

STEP 2

LET LENGTH OF SECOND BACKYARD BE Y

AREA=650

BREADTH=5M

ACCORDING TO THE QUESTION

L*B=650

L*5=650

L=650/5

=130M

L=130m

PERIMETER TO FIND THE FENCING=2(L+B)

                                                      =2(130+5)

                                                      =2*135

                                                        270M

SECOND BACKYARD HAS MORE FENCING AND BY 270-102

                                                                       =168M