in a competition a sprinterrinter starts from rest and achevies is a velocity of 30 minute second in the time of 60 second what is his average Alcreation
Answers
Answer:
Explanation:
15m/s
We know the total distance the sprinter covers, and we know the total time. However, since the acceleration isnt uniform, we cant calculate the velocity quite so simply. Rather, we need two equations, one for the first 5 0 meters of the race, and another for the second 5 0 meters. In the first 50 meters, the sprinter accelerates from an initial velocity of v
0
=0 to a final velocity of v in an amount of time, t
1
. We can express this relationship using the kinematic equation that leaves out velocity, and then solve for t:
x=x
0
+
2
1
(r+v
0
)t
1
50m=
2
1
vt
1
t
1
−
v
100m
In the last 5 0 meters of the race, the sprinter runs with a constant velocity of v , covering a distance of x = 50 m in a time t
2
, Solving for, t
2
we find:
t
2
=
v
50m
We know that the total time of the race, t
1
+t
2
=10s. With this in mind, we can add the two sprint times together and solve for v :
10s=
v
100m
+
v
50m
=
v
150m
v=
10s
150m
=15m/s