In a competitive exam, 5 marks are awarded for every correct answer and for every wrong answer, 2 marks are deducted. Sathwik scored 32 marks in this examination. If 4 marks had been awarded for each correct answer and 1 mark had been deducted for each incorrect answer, Sathwik would have scored 34 marks. If Sathwik attempted all the questions, how many questions were there in the test? TCS
Answers
Step-by-step explanation:
In given Question:-
Correct answer =5x and wrong answer=2y
Correct answer =4x and wrong answer= 1y
So,
5x -2y = 32
4x-2y =34------*2
Now
5x-2y =32
8x-4y=68
By solving
3x=36
x=12
Now to find ‘y’
5*12 -2y =32
60 -2y= 32
y=14
By adding x+y
12+24 =26
Questions in the test =26.
Given :- In a competitive exam, 5 marks are awarded for every correct answer and for every wrong answer, 2 marks are deducted. Sathwik scored 32 marks in this examination. If 4 marks had been awarded for each correct answer and 1 mark had been deducted for each incorrect answer, Sathwik would have scored 34 marks. If Sathwik attempted all the questions, how many questions were there in the test ?
Solution :-
Let us assume that, Sathwik answered x Questions correctly and y questions he gave wrong answer.
So,
→ Total marks for correct answer = 5 * x = 5x
and,
→ Total marks deducted for wrong answer = 2y .
given that, he scored 32 marks in this examination .
So,
→ 5x - 2y = 32 -------------- Eqn .(1)
Now, we have , If 4 marks had been awarded for each correct answer and 1 mark had been deducted for each incorrect answer, Sathwik would have scored 34 marks.
So,
→ 4x - y = 34 ------------- Eqn. (2) .
Multiply Eqn.(2) by 2 and subtracting Eqn.(1) from Eqn.(2) after that,
→ 2(4x - y) - (5x - 2y) = 2*34 - 32
→ 8x - 2y - 5x + 2y = 68 - 32
→ 3x = 36
dividing both sides by 3,
→ x = 12.
Putting value of x in Eqn.(2) ,
→ 4*12 - y = 34
→ y = 48 - 34
→ y = 14.
Therefore,
→ Total questions in the test = x + y = 12 + 14 = 26 (Ans.)
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