Question

In a competitive exam 50 students passed in English. 60 students passed in Mathematics. 40 students

passed in both the subjects. None of them fail in both the subjects. Find the number of students who

passed at least in one of the subjects ?​

Answer 1

Given:

• Students passed in English = 50.

• Students passed in Mathematics = 60.

• Students passed in both subjects = 40.

To Find:

• No. of students passed at least in one of subjects = ?

Solution:

Here,

• No. of students passed in English = 50 students.

• No. of students passed in Mathematics = 60 students.

• No. of students passed in both the subjects = 40 students.

★ Total No. of students who passed in English & Mathematics:

= No. of students passed in English + No. of students passed in Mathematics

= 50 + 60

= 110 Students.

★ Students passed at least in one of subject:

= No. of students passed in English & Mathematics - No. of students who passed in both the subjects

= 110 - 40

= 70 Students.

Thus,

• The no. of students who passed at least in one of subjects are 70.

Answer 2

❍ $\Large{\underline{\underline{\sf{Step\:by\:step\:explanation:}}}}$

Given that,

50 students passed in English.

60 students passed in Mathematics.

40 students passed in both the subjects.

We need to find the number of students who passed at least in one of the subjects.

___________

Students who passed in English and Maths =

students passed in English + students passed in Mathematics

:$\implies{\sf{50+60}}$

:$\implies{\sf{110}}$

Students who passed at least in one of the subjects =

Students passed in English and Maths - Students passed in both subjects.

:$\implies{\sf{110-40}}$

:$\implies{\boxed{\sf{\red{70}}}}$

Therefore, the number of students passed at least in one of the subjects is 70.

And we are done! :D

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