In a competitive exam, the number of passed students was four times the number of failed students. If there had been 35 fewer appeared students and 9 more had failed, the ratio of passed and failed students would have been 2 : 1, then the total number of students appered for the exam ?
A) 175
B) 165
C) 155
D) 145
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Let the number of failed students = x
Number of passed students = 4x
Therefore,
Total number of students = x + 4x = 5x
If there were 35 fewer students appeared and had 9 more failed, then the equation will be -
= 5x - 35
Number of failed students = x + 9
Number of passing students = ( 5x-35) - (x + 9)
= 4x - 44
( 4x - 44) : ( x + 9) = 2:1
2 ( x + 9 ) = 4x-44
2x + 18 = 4x - 44
2x - 4x = -44 - 18
-2x = -62
x = 31
Therefore total students = 5x = 5 × 31 = 155
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