Question

In a competitive exam there are 5 papers. The average score of Priyesh in first
three papers is 64 and his average score in last three papers is 85. If his average
score for all the papers is 75, what is his score in the third paper ?
1) 68 2) 78 4) 66
3) 75
5.72​

Answer 1

Step-by-step explanation:

let score in 3rd paper = x

total score in first three papers= 64×3 = 192

total score last three papers = 255

total score = 75×5 = 375 = 192 + 255 — x

x = 72