Question

In a compound, atoms of element Y form ccp
lattice and those of element X occupy 2/3rd of
tetrahedral voids. The formula of the
compound will be
[AIEEE 2008]
(a) X4Y3 (b) X2Y3, (c) X2Y (d) X3Y4​

Answer 1

Answer:

Let, the number of close packed spheres be N,

then:

The number of octahedral voids generated = N

The number of tetrahedral voids generated = 2N

Number of atoms of Y = N = 4

Number of atoms of X = 23×2N=23×8=163

∴ Formula of the compound will be X4Y3

Hence answer is (a)

please mark as brainliest answer

Answer 2

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\purple{R}}}}$

• ❤.. The number of tetralhedral voids formed is equal to twice the number of atoms of element B and only 2/3rd of these are occupied by the atoms of element A.
• ❤..Hence the ratio of the number of atoms of A and B is ${2×(2/3):1 or 4:3}$ and the formula of the compound is ${A4B3}$.