Question

In a compound AxBy,
(1) Mole of A = mole of B = mole of Ax By
(2) eq. of A = eq of B = eq. of AxBy
(3) yx mole of A = yx mole of B = (x + y) > mole of
AxBy
(4) y xmole of A = y xmole of B​

Answer 1

Explanation:

mole of a molecular of b