In a compound Carbon and Oxygen react in a ratio 3: 8 by mass to form carbon dioxide. What mass of oxygen is required to repeated to react completely with 9 g Carbon?
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Answers
Answered by
313
Carbon and oxygen reacts in a ratio 3:8 by mass to form Carbon dioxide
Hence the required reaction is ;
C + O2 --> CO2
Carbon : Oxygen = 3 : 8
Due to law of constant proportion, the mass ratio in which the reactants will react will remain constant.
Carbon --> 9 g
Oxygen --> ?
C : O2 = 3:8
9 : O2 = 3:8
9/O2 = 3/8
Mass of oxygen required
= (9/3)×8
= 3×8
= 24 g
______________________
Hence the required reaction is ;
C + O2 --> CO2
Carbon : Oxygen = 3 : 8
Due to law of constant proportion, the mass ratio in which the reactants will react will remain constant.
Carbon --> 9 g
Oxygen --> ?
C : O2 = 3:8
9 : O2 = 3:8
9/O2 = 3/8
Mass of oxygen required
= (9/3)×8
= 3×8
= 24 g
______________________
abhi178:
good answer sardar
Answered by
141
Given ratio of carbon and Oxygen by mass is 3:8
The mass of carbon is 9g
Let's think the mass of Oxygen is X g
Now,
C + O2 = CO2
According to the law of constant proportion,
Mass of carbon / Mass of Oxygen = 3 /8
9 / X = 3 / 8
or, X = 9 × 8 / 3
or, X = 72/ 3
or, X = 24 g
So, 24 g Oxygen is required.
Hope it helps.
The mass of carbon is 9g
Let's think the mass of Oxygen is X g
Now,
C + O2 = CO2
According to the law of constant proportion,
Mass of carbon / Mass of Oxygen = 3 /8
9 / X = 3 / 8
or, X = 9 × 8 / 3
or, X = 72/ 3
or, X = 24 g
So, 24 g Oxygen is required.
Hope it helps.
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