Question

In a compound of ammonia ,nitrogen and hydrogen are present in the ratio 14:3 by mass .If the actual mass of hydrogen is 9 g , then what would be the actual mass of nitrogen present in it

Answer 1

Mass of N (say 'n') to H (say 'h') ratio is given (14:3) ;
=> n/h =14/3
We are given actual mass of H in the compound => h= 9 g
=> n/9= 14/3
=> n (actual mass of N in compound) =
42g
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hope it helps !

Answer 2

Lets take the amount of nitrogen present in Ammonia to be 14 x .

Also ,amount of hydrogen present in Ammonia = 3 x

We are given that the actual mass of hydrogen in Ammonia s 9 grams

That is ,
3 x = 9 grams
x = 9 / 3 = 3

Therefore ,
Amount of Nitrogen present in Ammonia = 14 x = 14 × 3
= 42 grams