Question

In a compound, the following elements have the given percentages: H-4.07% C-24.27% Cl-71.65% Molecular mass=98.96g Calc. Empirical Formula and Molecular formula

Answer 1

Tag me brain list...

.step 1

Divide the given percentages of atoms with their molecular masses

H---4.07/1 =4.07

C---24.27/12 =2.02

Cl--71.65/35.5=2.01

step 2

divide all values with the lowest value obtained.

H---4.07/2.01=2

C---2.02/2.01=1

Cl---2.01/2.01=1

therefore the empirical formula is

CH

2

Cl

WEIGHT OF EMPIRICAL FORMULA=12+2+35.5=49.5

Given molecular weight =98.96 which is double of empirical weight .therefore molecular formula is C 2 H4 Cl2

Thank-you...

.

Answer 2

Explanation:

i think it will be correct . please recheck it