In a compound, X and Y atom;
weight% of X = 75.8%
weight% of Y = 24.2%
Atomic weight of X and Y are 24 and 16 respectively.
Calculate the empirical formula of the compound.
Answers
Answer:
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Explanation:
Element one = X (Given)
Element two = Y (Given)
Atomic weight of X = 24 (Given)
Atomic weight of Y = 16 (Given)
Percentage of element X = 76 (Given)
Percentage of element Y = 24 (Given)
Thus,
Mass ratio of X = 76/75 = 1.01
Mass ratio of Y = 24/16 = 1.5
Atomic ratio of X = 1.01/1.01 = 1x 2 = 2
Atomic ratio of Y = 1.5/1.01 = 1.48≈1.5 x 2 = 3
Therefore, the empirical formula will be - X₂Y₃.
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Answer:
Correct option is
Correct option isC
Correct option isCX
Correct option isCX 2
Correct option isCX 2
Correct option isCX 2 Y
Correct option isCX 2 Y 3
Correct option isCX 2 Y 3
Correct option isCX 2 Y 3
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atoms
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.5
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 16
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2 1.5×2=3
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2 1.5×2=3 =1.51
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2 1.5×2=3 =1.51Therefore, the formula is X
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2 1.5×2=3 =1.51Therefore, the formula is X 2
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2 1.5×2=3 =1.51Therefore, the formula is X 2
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2 1.5×2=3 =1.51Therefore, the formula is X 2 Y
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2 1.5×2=3 =1.51Therefore, the formula is X 2 Y 3
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2 1.5×2=3 =1.51Therefore, the formula is X 2 Y 3
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2 1.5×2=3 =1.51Therefore, the formula is X 2 Y 3 .
Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2 1.5×2=3 =1.51Therefore, the formula is X 2 Y 3 .Hence, option C is correct.