Chemistry, asked by sahajvirk16, 1 month ago

In a compound, X and Y atom;
weight% of X = 75.8%
weight% of Y = 24.2%
Atomic weight of X and Y are 24 and 16 respectively.
Calculate the empirical formula of the compound.

Answers

Answered by joshipratyaksh08
6

Answer:

Hi friends

Explanation:

Element one = X (Given)

Element two = Y (Given)

Atomic weight of X = 24 (Given)

Atomic weight of Y = 16 (Given)

Percentage of element X = 76 (Given)

Percentage of element Y = 24 (Given)

Thus,

Mass ratio of X = 76/75 = 1.01

Mass ratio of Y = 24/16 = 1.5

Atomic ratio of X = 1.01/1.01 = 1x 2 = 2

Atomic ratio of Y = 1.5/1.01 = 1.48≈1.5 x 2 = 3

Therefore, the empirical formula will be - X₂Y₃.

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Answered by SUPERBRAIN2006
1

Answer:

Correct option is

Correct option isC

Correct option isCX

Correct option isCX 2

Correct option isCX 2

Correct option isCX 2 Y

Correct option isCX 2 Y 3

Correct option isCX 2 Y 3

Correct option isCX 2 Y 3

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atoms

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.5

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 16

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2 1.5×2=3

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2 1.5×2=3 =1.51

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2 1.5×2=3 =1.51Therefore, the formula is X

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2 1.5×2=3 =1.51Therefore, the formula is X 2

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2 1.5×2=3 =1.51Therefore, the formula is X 2

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2 1.5×2=3 =1.51Therefore, the formula is X 2 Y

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2 1.5×2=3 =1.51Therefore, the formula is X 2 Y 3

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2 1.5×2=3 =1.51Therefore, the formula is X 2 Y 3

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2 1.5×2=3 =1.51Therefore, the formula is X 2 Y 3 .

Correct option isCX 2 Y 3 Element Percentage At.mass Relative no. Ratio of atomsX 75.8 75 7.575.8 1×2.2 =1.01Y 24.2 16 1624.2 1.5×2=3 =1.51Therefore, the formula is X 2 Y 3 .Hence, option C is correct.

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