In a concave mirror an object is placed at distance of 30 cm in front of mirror. Radius of curvature of the mirror is 40 cm find the position of image
Answers
Explanation:
position of image is beyond c
Explanation:
Answer :-
Image distance is -24 cm.
Explanation :-
Given :-
Object distance (u) = -12 cm
Radius of curvature (r) = -16 cm
To find :-
Position of the image/Image distance (v) = ?
Solution :-
Radius of curvature (r) = -16 cm
Focal length (f) = r/2
-16/2
∴ Focal length is -8 cm.
________________________________
Using mirror formula :
1/v + 1/u = 1/f
1/v + 1/(-12) = 1/(-8)
1/v = 1/-8 - 1/-12
1/v = (1 × -3 - 1 × -2)/24
1/v = -1/24
v = -24
∴ Image distance (v) is -24 cm.EXPLANATION.
Water flows through a circular pipe.
Internal diameter = 2 cm.
Rate = 6m/sec into a circular tank.
The radius of whose base = 60 cm.
To find the rise in the level in water in 30 minutes.
As we know that,
Diameter = 2 x Radius.
Radius = Diameter/2.
Radius = 2/2 = 1 cm = 1/100 m.
Volume of cylinder = πr²h.
Volume of water flows through a circular pipe in 1 seconds = πr²h.
π x (1/100)² x 6.
The raise in the water level in 30 minutes = π x (1/100)² x 6 x 30 x 60.
Radius whose base = 60 cm = 60/100 m.
Volume = πr²h.
⇒ π x (60/100)² x h.
⇒ π x (60/100)² x h = π x (1/100)² x 6 x 30 x 60.
⇒ 60/100 x 60/100 x h = 1/100 x 1/100 x 6 x 30 x 60.
⇒ 60 x 60 x h = 6 x 30 x 60.
⇒ 60 x h = 6 x 30.
⇒ 10 x h = 30.
⇒ h = 3m.