Question

in a concave mirror find V and draw a rat diagram ​

Answer 1

Answer:

please mark as brainlist please

Answer 2

In the given figure a ray of light BP' traveling parallel to the principal axis PC is incident on a spherical mirror PP'. The distance PF is equal to the focal length f. C is the centre of curvature. The distance PC is equal to the radius of curvature R of the mirror. P'C is the normal to the mirror at the point of incidence P'. In the given figure a ray of light BP' travelling parallel to the principal axis PC is incident on a spherical mirror PP'. After reflection, it goes along P'R, through the focus F.

For concave mirror,

∠BP ′ C=∠P ′

CF (alternate angle)∠BP, C=∠CP ′ F (law of reflection ∠i=∠r)

Hence ∠P , CF=∠CP ′ F

∴△FP ′ C is isosceles.Hence P ′ F=PF

if aperture is small ,point P ′ is close to point Pthen, P ′ F=PF

∴ PF=FC= 21

PCf= 21R

According to mirror equation of concave mirror,

u1 + v1 = f1

where:

u: Object distance

v: Image distance

f: Focal length

Speed of light is higher in rarer medium.

v 2<v 1

Frequency of light does not change on change of medium.f 1 =f2λ 1v 1= λ 1v 2λ 1λ2 =v 1v2 <1

Hence, when light enters from rarer to denser medium, wavelength reduces but frequency is unchanged.