Question

In a conductor, 6.25 × 1016 electrons flow from its end A to B in 2 s. Find the current flowing through the conductor. (e = 1.6 × 10-19 C)​

Answer 1

Solution :-

Given :-

Number of electrons flowing through the conductor,

=> n = 6.25 × 10^{16} electrons.

• Time taken to flow from A to B = 2 s and e = 1.6 × 10^{-19} C

• Let I be the current flowing through the conductor

Now, I = ne / t

Therefore I = [(6.25 × 10^{16}) (1.6 × 10^{-19})] / 2

=> I = 5 × 10^{-3} A

=> I = 5 m A

Hence, 5 mA current flows from B to A.