In a conference of 8 persons, if each person shake hand with the other one only, then the total number of shake hands shall be
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Person 1: He can shake hands with 7 new people. (7)
Person 2: He can shake hands with 6 new people.(6)
Person 3: He can shake hands with 7 new people.(5)
Person 4: He can shake hands with 6 new people.(4)
Person 5: He can shake hands with 5 new people.(3)
Person 6: He can shake hands with 4 new people.(2)
Person 7: He can shake hands with 3 new people.(1)
Person 8: He can shake hands
So total handshake is 7+6+5+4+3+2+1
So it forms a A.P
Sum → n(n-1)/2
Sum →8(7)/2
Sum →56/2
Sum →23
Person 2: He can shake hands with 6 new people.(6)
Person 3: He can shake hands with 7 new people.(5)
Person 4: He can shake hands with 6 new people.(4)
Person 5: He can shake hands with 5 new people.(3)
Person 6: He can shake hands with 4 new people.(2)
Person 7: He can shake hands with 3 new people.(1)
Person 8: He can shake hands
So total handshake is 7+6+5+4+3+2+1
So it forms a A.P
Sum → n(n-1)/2
Sum →8(7)/2
Sum →56/2
Sum →23
Answered by
1
TOTAL PERSON = 8
BY USING FORMULA = N(N-1)/2
- n= 8
8(8-1)/2
= 8*7/2
= 56/2
= 28 Times
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