in a consistently of 80500 voters 60% cast their votes and in a straight contest between two candidates the winner obtained 2600 votes more than his opponent.what is percentage of votes cast in favour of each candidates?
Answers
55.39% in favour of winning candidate
and 44.61 in favour of loosing candidate
Answer:
The winning party got 25,450 /53% votes and the opposite party got 22,850/ 47% votes
Step-by-step explanation:
No.of voters voted = 80500 x 60/100
= 805 x 60
=48,300 voters
let the no. of voters voted to the opposite party be 'x' votes
and the no.of voters voted to the winning party = x+2600
According to the given condition
x + x + 2600 = 48,300
2x + 2600 = 48,300
2x = 48,300 - 2600
2x = 45,700
x = 45,700 / 2
x = 22,850 votes
therefore the no. of votes voted to the opposite party = 22,850 votes
the no. of votes voted to the winning party = 22,850 + 2600
= 25,450 votes
therefore 25,450 votes were given to the winning party.
percentage of voters voted in the winning party = 25,450/48,300 x100
= 53 % approx
percentage of voters voted in opposite party = 22,850/48,300 x 100
= 47 % approx
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