in a container 2 gram as 22 gram and 2 and 2 gram O2 are present in which has the largest number of atoms
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6.023×10
23
=0.376×10
23
atoms.
Molecular mass of O
2
=32g
Number of atoms in 32 g of O
2
=2×6.023×10
23
So, number of atoms in 1 g of O
2
=
32
2×6.023×10
23
×1=0.376×10
23
atoms.
The molecular mass of O
2
=48g
Number of atoms in 48gof O
2
=3×6.023×10
23
So, number of atoms n 1g of O
3
=
48
3×6.023×10
23
×1
=0.376×10
23
Explanation:
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