Question

In a continuous frequency distribution table if the mid -point of a class is 42 and class size is 10 then let us write the upper and lower limit of the class
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Answer 1

Answer:

⇒  Let upper limit and lower limit be x and y

⇒  2x+y=42                   [ Given ]

∴  x+y=84                     ------ ( 1 )

Now, according to the question,

⇒  x−y=10                  ------ ( 2 )

Adding equation ( 1 ) and ( 2 ) we get,

2x=94

∴  x=47

And 47−y=10

∴  y=37

∴  Required class interval =37−47

Answer 2

Answer:

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