Question

in a convex mirror the radius of curvature R is 1.6cm if the object infront of 1cm in a convex mirror what about the image distance and its nature??

Answer 1

R = 1.6cm
f= R/2
= 0.8cm
u=-1cm

1/f = 1/u + 1/v
1/0.8 = -1 + 1/v
10/8 = -1 + 1/v
5/4 = -1 + 1/v
5/4 + 1 = 1/v
9/4 = 1/v
v = 4/9
= 0.44cm
nature of the image is erect and virtual