Question

in a cooperative society the number of men is thrice the number of women 29 women and 16 men more joined the society and now the number of men is doubled the number of women how many women were there in the society at first

Answer 1

Let the no. of men be x & women be y.

As per first given condition,
x = 3y

As per second given condition,
(x+16) = 2(y+29)
x+16 = 2y+58
x-2y = 58-16
3y-2y = 58-16
y = 42

x = 3y
x = 3(42)
x = 126

At first, there were 126 men and 42 women.

Answer 2

Answer:

refer to attachment

Step-by-step explanation:

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