Question

In a , coordinates of a are (3, 4) and the equations of the medians through b and c are respectively . Then area of (in square units) is:

Answer 1

Answer:

Step-by-step explanation:

ABC is a triangle in which A(1,2). Mid point of AC is D and mid point of AB is E.

Equation of mdn BD is x+y=4… ….(1).

Equation of mdn CE is x=4…………(2)

let coordinate of B(p,q) and C(r,s)

coordinate of E [(p+1)/2,(q+2)/2]

Point E lies on CE [x=4 ] , therefore

(p+1)/2=4

p+1=8

p=8–1

p=7

Point B(p,q) lies on BD [x+y=4].

p+q=4

7+q=4

q=-3 . Theredore B(7,-3) , Answer.

Point C(r,s) lies on CE[ x = 4]

r=4

coordibate of D[(r+1)/2,(s+2)/2]

Similarly point D lies on BD[x+y=4].

(r+1)/2+(s+2)/2=4

r+s=5 , put r = 4

4+s=5 =>s=1 , therefore C(4,1) , Answer