in a coty the fare of a taxi for the first kilometre is 5 rs. and after that it is 3 rs. if the distance covered is x km. and fare is y, then express it in the form of equation
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Answered by
1
The answer is 5+3(x-1)=
5
5+3x-3=y.
2+3x-y=0
5
5+3x-3=y.
2+3x-y=0
rekhadarjiptp:
thanks
Answered by
1
May be 5+3x=y
5+3x-y=0
5+3x-y=0
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