Question

In a cpu shared system, if z is the probability that any cpu

Answer 1

Explanation:

There are N - CPUs , and exactly one of them uses the bus.

There are N - CPUs , and exactly one of them uses the bus.Using binomial distribution, nCx * px * (1- p)n-x

There are N - CPUs , and exactly one of them uses the bus.Using binomial distribution, nCx * px * (1- p)n-x { Here x is number of success , p is probability of success in one trial,

There are N - CPUs , and exactly one of them uses the bus.Using binomial distribution, nCx * px * (1- p)n-x { Here x is number of success , p is probability of success in one trial, n is total number of trials }

There are N - CPUs , and exactly one of them uses the bus.Using binomial distribution, nCx * px * (1- p)n-x { Here x is number of success , p is probability of success in one trial, n is total number of trials } probability that only one CPU uses the bus = NC1 * z1 * (1-z)N-1 = A(Ans)

There are N - CPUs , and exactly one of them uses the bus.Using binomial distribution, nCx * px * (1- p)n-x { Here x is number of success , p is probability of success in one trial, n is total number of trials } probability that only one CPU uses the bus = NC1 * z1 * (1-z)N-1 = A(Ans) {Here z is probability of CPU using bus & we want exactly one Cpu to use the bus

There are N - CPUs , and exactly one of them uses the bus.Using binomial distribution, nCx * px * (1- p)n-x { Here x is number of success , p is probability of success in one trial, n is total number of trials } probability that only one CPU uses the bus = NC1 * z1 * (1-z)N-1 = A(Ans) {Here z is probability of CPU using bus & we want exactly one Cpu to use the bus at a time so, NC1 }..

Answer 2

Answer:

There are N - CPUs , and exactly one of them uses the bus.

There are N - CPUs , and exactly one of them uses the bus.Using binomial distribution, nCx * px * (1- p)n-x

There are N - CPUs , and exactly one of them uses the bus.Using binomial distribution, nCx * px * (1- p)n-x { Here x is number of success , p is probability of success in one trial,

There are N - CPUs , and exactly one of them uses the bus.Using binomial distribution, nCx * px * (1- p)n-x { Here x is number of success , p is probability of success in one trial, n is total number of trials }

There are N - CPUs , and exactly one of them uses the bus.Using binomial distribution, nCx * px * (1- p)n-x { Here x is number of success , p is probability of success in one trial, n is total number of trials } probability that only one CPU uses the bus = NC1 * z1 * (1-z)N-1 = A(Ans)

There are N - CPUs , and exactly one of them uses the bus.Using binomial distribution, nCx * px * (1- p)n-x { Here x is number of success , p is probability of success in one trial, n is total number of trials } probability that only one CPU uses the bus = NC1 * z1 * (1-z)N-1 = A(Ans) {Here z is probability of CPU using bus & we want exactly one Cpu to use the bus

There are N - CPUs , and exactly one of them uses the bus.Using binomial distribution, nCx * px * (1- p)n-x { Here x is number of success , p is probability of success in one trial, n is total number of trials } probability that only one CPU uses the bus = NC1 * z1 * (1-z)N-1 = A(Ans) {Here z is probability of CPU using bus & we want exactly one Cpu to use the bus at a time so, NC1 }..