Question

In a cricket match A, B and C together scores 108 runs, B and C together 90 and A
and C together 51. Find the number of runs scored by each.
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Answer 1

Answer:

A= 18 ; B= 57 ; C= 33

Step-by-step explanation:

A= ABC - BC = 108 - 90 = 18

B= ABC - AC = 108 - 51 = 57

C= AC - A = 51 - 18 = 33

A+B+C = 108

18+57+33=108

Answer 2

The number of runs scored by each of A, B, and C are 18, 57, and 33 runs, respectively.

Given:

Runs scored by A, B and C=108

Rus scored by B and C=90

Runs scored by A and C=51

To find:

The number of runs scored by each

Solution:

We can obtain the required value by substituting the values of the runs scored.

We know that the runs scored by A, B and C=108

So, A+B+C=108 (1)

Similarly, B+C=90 (2)

A+C=51 (3)

Substituting (2) in (1),

A+90=108

A=108-90

A=18 runs

Now, putting A=18 in (3),

18+C=51

C=51-18

C=33 runs

On putting C=33 in (2), we get

B+33=90

B=90-33

B=57 runs

Therefore, the number of runs scored by each of A, B, and C are 18, 57, and 33 runs, respectively.

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