Question

In a cricket match a bastwoman hits a boundary 5timand30balls she plays.find the probability that she did not hit a boundary

Answer 1

Answer:

P( not boundry ) = 5/6

Step-by-step explanation:

total no. of event (balls) = 30

no of boundaries = 5

no. of non-boundary shots = 30 - 5 = 25 ( favorable outcome)

p of non boundary = no. fav. outcomes / total no. of evets

                                  = 25/30 = 5/6

Answer 2

$\huge{\mathcal{\pink{a}\green{N}\red{S}\blue{w} {E}\green{r}}}$

Step-by-step explanation:

(➜In a cricket match a batswoman hit a boundary 6 times out of 30 balls she plays.

Total number of outcomes = 30

We have to find the probability that she did not hit a boundary.

➜Number of favourable outcomes = 30 - 6 = 24 (in which she didn't hit the boundary)

Now, Probability =

$\purple{\sf{\frac{Number\:of\:favourable\:outcomes}{Total\:number\:of\:outcomes}}}$

➜Total number of outcomes

Number of favourable ooutcome

$\Rightarrow\:\sf{\frac{24}{30}}⇒ </p><p>30</p><p>24$

On simplifying we get,

$\Rightarrow\:\sf{\frac{4}{5}}⇒ </p><p>5</p><p>4$

so,, your correct answer is here.