Question

In a cricket match a batsman hit a boundary 6 times out of 30 balls he plays. Find the probability that he hit a boundary

Answer 1

p(E)=n(E)/n(S)

n(E)=6

n(S)=30

therefore,p(E)=6/30

=1/5

Answer 2

$\fbox\pink{S}\fbox\blue{O}\fbox\green{L}\fbox\red{U}\fbox\purple{T}\fbox\orange{I}\fbox\pink{O}\fbox\red{N}$

Accroding to the question,

• Total number of balls = 30
• Numbers of baundary = 6

So, number of times batsman didn't hit the boundary = (30-6)=24

Probability he didn't hit a boundary = 24/30=4/5