Question

in a cricket match,a batsman hit a boundry 6 times out of 30 balls she plays . find the probability that she did not hit a boundrey​

Answer 1

Answer:

1/5

Step-by-step explanation:

6/30 - cancelling out by 6

=1/5

Answer 2

Answer:

1/5 is the answer

Step-by-step explanation:

Sample Space S= { 1,2,3,...,30}

Therefore n(s) = 30

let A be the number of times batsman hits a boundary

A = { 1,2,3,4,5,6 }

n(A) = 6

Therefore P(A) = n(A)/n(s) = 6/30 = 1/5