Question

in a cricket match a batsman hit boundary 6 times out of 30 ball he plays.find the probability that he did hit a boundary

Answer 1

Ans.

The probability is
$= \frac{6}{30} \\ = \frac{1}{5}$

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Answer 2

Total number of balls = 30

Number of times boundary is hit = 6

Number of times boundary is not hit = Total number of balls - Number of times boundary is hit

Number of times boundary is not hit = 30 - 6 = 24

Here, favourable outcomes i.e. number of times boundary is not hit = 24

total number of outcomes i.e. total number of balls = 30

Required Probability (not hit a boundary) = Favourable outcomes ÷ Total number of outcomes

Required Probability (not hit a boundary) = 24/30

Required Probability (not hit a boundary) = 4/5

∴ Required Probability (not hit a boundary) = $\frac{4}{5}$

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