in a cricket match a batsman hit the boundary 8 times out of 50 balls than the probability that she did not hit the boundary is
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a batsman hits the boundary 8 times = 8 balls
n(A) = 8 ; n(S) = 50
p(A) = n(A)/n(S) = 8/50
now, we have to find that the batsman didn't hit the boundary:
1 - 8/50 =
42/50 (or) 21/25
HOPE IT HELPS YOU AND
MARK ME AS BRAINLIEST
n(A) = 8 ; n(S) = 50
p(A) = n(A)/n(S) = 8/50
now, we have to find that the batsman didn't hit the boundary:
1 - 8/50 =
42/50 (or) 21/25
HOPE IT HELPS YOU AND
MARK ME AS BRAINLIEST
Answered by
3
HEYA MATE, HERE IS UR ANSWER ______________
P(hit the boundary)=8/50
P (not hit a boundary )=1-8/50
=50-8/50
=42/50
=21/25
_____☆☆HOPE THE ANSWER HELPS YOU. ☆☆___☆☆BE BRAINLY ☆☆
P(hit the boundary)=8/50
P (not hit a boundary )=1-8/50
=50-8/50
=42/50
=21/25
_____☆☆HOPE THE ANSWER HELPS YOU. ☆☆___☆☆BE BRAINLY ☆☆
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