in a cricket match, a batsman hits a bondry 6 times out of 90 balls he play. find the probability that he (a) hit a boundary (b) did not hit a boundary.
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Answered by
6
Answer:
Step-by-step explanation:
a)
Probability =Number of requird outcomes/total number of outcomes
=6/90
=1/15
b)
Number of times he did not hit boundary =total number of ball he played-balls he played boundary
=90-6=84
=>84/90
=14/15
Answered by
3
Total events = 90
1). favourable events for hit a bondry = 6
p( for hit a boundary)= 6/90=1/15
2). favourable events for not hits = 84
p(for not hit a boundary )= 84/90
=14/15
1). favourable events for hit a bondry = 6
p( for hit a boundary)= 6/90=1/15
2). favourable events for not hits = 84
p(for not hit a boundary )= 84/90
=14/15
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