Question

in a cricket match, a batsman hits a bondry 6 times out of 90 balls he play. find the probability that he (a) hit a boundary (b) did not hit a boundary.

Answer 1

Answer:

Step-by-step explanation:

a)

Probability =Number of requird outcomes/total number of outcomes

=6/90

=1/15

b)

Number of times he did not hit boundary =total number of ball he played-balls he played boundary

=90-6=84

=>84/90

=14/15

Answer 2

Total events = 90
1). favourable events for hit a bondry = 6
p( for hit a boundary)= 6/90=1/15
2). favourable events for not hits = 84
p(for not hit a boundary )= 84/90
=14/15