Question

In a cricket match, a batsman hits a boundary 10 times out of 40 balls he plays. Find the probability that he did not hit a boundary.

Answer 1

Answer:

total no of times balls was thrown = 40

no of times he hits the boundary= 10

so,. no of times he didn't hits the boundary =(40-10)

= 30.

probability of not hitting the boundary = 30/40

=>3/4

hope this helps you.

Answer 2

Answer:

The probability that he did not hit a boundary = 0.75

Step-by-step explanation:

• Probability is a measure of the likelihood of an event to occur.
• Many events can be predicted with certainty but many cannot.
• We can just predict the chance of some events.

The number of balls played by the batsman = 40

Total number of trials = 40

The number of times he hit the boundary = 10

The number of times he doesn't hit the boundary = 40-10

                                                                                   = 30

Probability = Number of favourable outcomes/total number of trials

The probability that he did not hit a boundary = $\frac{30}{40}$

                                                                            =$\frac{3}{4}$

Answer - The probability that he did not hit a boundary = 0.75

Learn more about probability by clicking on the links given below-

https://brainly.in/question/7015096?referrer=searchResults

https://brainly.in/question/7015096?referrer=searchResults