Question

In a cricket match a batsman hits a boundary 10 times out of 36 balls he

plays. Find the probability that he does not hit the boundary. explain​

Answer 1

Answer:

i'll say 5/18

i think

Answer 2

GIVEN; NO. OF TIMES BOUNDARIES HIT BY BATSMAN = 10

TOTAL NO. OF BALLS PLAYED BY BATSMAN = 36

TO FIND; PROBABILITY OF BATSMAN NOT HITTING BOUNDARY

SOLUTION;

THEN, NO. OF BALLS BATSMAN DON'T HIT BOUNDARY => TOTAL NO. OF BALLS PLAYED - NO. OF BALLS BATSMAN HITTED BOUNDARY

=> 36 - 10

=> 36 - 10 => 26

NOW ,LET THE PROBABILITY OF BATSMAN NOT HITTING BOUNDARY BE P(E)

AS WE KNOW,

PROBABILITY OF OCCURING OF AN EVENT = NO. OF TIMES EVENT OCCURRED / TOTAL NO. OF TRIALS

PROBABILITY OF BATSMAN NOT HITTING BOUNDARY ;=> NO. OF BALLS BATSMAN HITTED BOUNDARY / TOTAL NO. OF BALLS PLAYED

=> P(E) = 26 / 36

=> P(E) = 0.723

THIS MEANS THAT OUT OF 100 THERE ARE APPROX 72 % CHANCES THAT THE BATS MAN WILL NOT HIT BOUNDARY.

THANKS FRIEND, HOPE IT HELPS YOU .