Question

In a cricket match a batsman hits a boundary 4 times out of 32 balls he plays. what is the probability that he did not hit a boundary?

Answer 1

P(Noboundary) = 1-(4/32)
= (32-4)/32
=28/32
=7/8


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Answer 2

Total no. of balls he played = 32
Balls he didn't hit a boundary = 32 - 4 = 28
The required probability that he didn't hit a ball = 28/32 = 7/8