Question

In a cricket match, a batsman hits a boundary 6 times out of 36 balls he plays. The probability that he di
not hit a boundary
answer should get5/6
but i want explanation plz help me​

Answer 1

Answer:

5/6

Step-by-step explanation:

balls he hit for boundary = 6

no. of balls he didn't hit for boundary

= 36-6 = 30

probability that he didn't hit boundary

= 30/36 = 5/6

Answer 2

5/6 is probability that batsman  did not hit a boundary if he hits a boundary 6 times out of 36 balls he plays in a cricket match

Step-by-step explanation:

In a cricket match, a batsman hits a boundary 6 times out of 36 balls he plays

Total Balls Played = 36

Total Boundary Hits = 6

Number of Balls on which boundary not hitted = Total Ball Played - Ball on which boundary hitted

= 36 - 6

= 30

Number of Balls on which boundary not hitted = 30

probability that he did not hit a boundary =  Number of Balls on which boundary not hitted/ total balls played

= 30/36

= 5/6

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