In a cricket match, a batsman hits a boundary 6 times out of 30 balls plays. Find
the probability that on a ball played a)He hits boundary (b) he does not hits a boundary
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Answer:
The Batsman hits the boundary = 6 times
The Batsman doesn't hit the boundary=30-6=24
total number of balls played = 30
Step-by-step explanation:
let
probability of the Batsman hits the boundary = A
p(A) = 6/30= 0.2
probability of the Batsman doesn't hit the boundary = B
p(B) = 24/30= 0.8
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