Question

In a cricket match, a batsman hits a boundary 8 times out of 40 balls he plays. Find the

probability that, he did not hit a boundary

Answer 1

$\underline \bold{Answer}$

⇒ 0.8

$\underline \bold{Explanation}$

Let E donate the event that the batsman did not hit a boundary.

Number of trial in which E event has occurred

= Number of ball - Number of ball hit the boundary

$= \: 40 - 8 \\ = \: 32$

$\fbox{ \large \bold{Probablity = \frac{No. \: of \: favourable \: outcomes}{Total \: No. \: of \: outcomes }}}$

$P(E) = \large{\frac{ 32}{ 40}}$

$\large{\frac{4}{5} }$

→ 0.8

Therefore, the probablity of event in which the batsman didn't hit the boundary is 0.8

Answer 2

Step-by-step explanation:

here is ur answer thank u