Question

In a cricket match, a batsman hits a boundary
9 times out of 45 balls he plays, then the
probability that he
did not hit á boundary is?
A. 1 1/4
B.4/5
C.1/5
D.2/5​

Answer 1

Answer:

$\frac{1}{5} is \: the \: correct answer \: mate \: {$

Answer 2

Answer:

B. 4 / 5

Step-by-step explanation:

No. of balls = 45

No. of times he hits a boundary = 9

No. of times did not hit a boundary = 45 - 9 = 36

The probability that he  did not hit a boundary is,

= No. of times did not hit a boundary / No. of balls

= 36 / 45

= 4 / 5