Question

In a cricket match a batsman hits a boundary six times out of 30 balls he plays .Find the probability that he did not hit a boundary​

Answer 1

$\bold{Given} \\ </p><p></p><p>Total \: number \: of \: balls \: played= \: 30 \\ </p><p></p><p>Number \: of \: times \: batsman \: hits \: a \: boundary= \: 6 \\ </p><p></p><p>Number \: of \: times \: batsman \: doesnot \: hit \: a \: boundary= \: 30−6=24 \\ \\ </p><p></p><p></p><p>Probability \: that \: on \: a \: ball \: played \: he \: doesnot \: hits \: a \: boundary \\ = \frac{Frequency \: when \: the \: batsman \: doesnot \: hits \: a \: boundary}{</p><p>Total \: number \: of \: balls \: played} \\ \\ = \frac{24}{30} = 0.8</p><p>$

Answer 2

Probability=Frequency that the batsman do/Total number of ball.

24/30=0.8

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