In a cricket match a batsman hits
boundary 10 times out of 36
balls the plays. find the probability that he does not hit the boundary
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Answered by
2
Answer:In a cricket match a batsman hits a boundary 10 times out of 36 ball he plays find the probability that he does not hit the boundary. We need the probability of not hitting the boundary so we have to minus the 10balls out of 36total balls=36-10=26.as we know we have to devide 26/total no.
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Answered by
3
Answer:
26/36
Step-by-step explanition:
no.of times boundary:10/36
no.of times no boundary: 36-10= 26/36
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