Question

In a cricket match, a batsman hits boundary 8 times out of 40 balls

he play. Find the probability that he didn’t hit boundary?​

Answer 1

Answer:

Let n(E) is the event that the batsman did not hit a boundary.

Number of balls in which batsman not hit the boundary = Number of ball - Number of ball hit the boundary

n(E) = 40 -8 = 32

Total Number of balls n(S) = 40

Probability = n(E) / n(S) = 32/40 = 4/5

Answer 2

Total number of outcomes = 40

No. of times batsman hit boundary = 8 times.

⟹ Total no. possible outcomes = 40 - 8

= 32

$\sf{Probability\: =\: {\dfrac{No.\: of\: possible\: outcomes}{Total\: no.\: of\: outcomes}}}$

According to formula,

$\sf{Probability\: =\: {\dfrac{32}{40}}}$

$\sf{\implies\: Probability\: =\: {\dfrac{4}{5}}}$