In a cricket match, a batsman hits six 8 times out of 32 balls played. Find the probability that a six is not hit in a ball. I m nt able 2 do it... Plz. Answr it quckly...
Answers
Answered by
6
Hey..
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Total no of balls played by a batsman = 32
No of balls, he hits six = 8
=) No of balls, he did not hitted six = 32 - 8
= 24
Hence,
Probability that a six is not hitted by a batsman = No of balls, he did not hitted six / Total No of balls played by him.
=) P = 24/32
= 3/4.
Hope it's helpful to u.
--------------------------_-------------------------------
Total no of balls played by a batsman = 32
No of balls, he hits six = 8
=) No of balls, he did not hitted six = 32 - 8
= 24
Hence,
Probability that a six is not hitted by a batsman = No of balls, he did not hitted six / Total No of balls played by him.
=) P = 24/32
= 3/4.
Hope it's helpful to u.
Answered by
0
in 32 balls he hits 8 times so probability of not hitting a ball is 32/8 so ans is 4/1
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