Question

in a cricket match a batswoman hits a boundary 6 times out of 30 balls she plays find the probability that she did not hit a boundary ​

Answer 1

n(S)=30

Event A is that the batswoman did not hit the ball

Therefore,

n(A)=30-6=24

p(A)=n(A)/n(S)=24/30=4/5

Therefore, probability is 4/5

Answer 2

Answer:

Total no. of outcomes = Total no. of times the balls was thrown = 30

No. of times balls hits the boundary = 6

$\\ \sf \qquad p(e) = p(hitting \: \: the \: \: boundary) = \frac{6}{30} \\ \\ \\ \sf \qquad \: p(e) = p \: (not \: \: hitting \: \: the \: \: boundary)$

$\\ \sf \: P(E) + P( - E) = 1 \\ \\ \\ \sf \: \cancel\frac {6}{30} + P \: ( \: not \: \: hitting \: \: the \: \: boundary \: ) = 1 \\ \\ \\ \sf P \: ( \: not \: \: hitting \: \: the \: \: boundary \: ) = 1 - \frac{1}{5} \\ \\ \\ \implies \sf \: \frac{5 - 1}{5} \\ \\ \\ \implies \sf \blue{ \frac{4}{5} }$