Question

in a cricket match a batswoman hits a boundary 6 times out of 30 balls she plays find the probability that she did not hit a boundary​

Answer 1

Answer:

$\frac{4}{5}$

Step-by-step explanation:

S = { 6 boundaries, 24 normal balls}

n(S) = 30

i. A --> The number of times the batswoman did not hit a boundary.

A = { 24 normal balls }

n(A) = 24

Probability of A = P(A) = $\frac{n(A)}{n(S)}$ = $\frac{24}{30}$ = $\frac{4}{5}$